# Average Flex Codechef Solution

#### ByBrokenprogrammers

Dec 20, 2022

Hello Programmers In this post, you will know how to solve the Average Flex Codechef Solution. The Problem Code: AVGFLEX

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Codechef by yourself. If you find any difficulty after trying several times, then you can look for solutions.

### Problem

There are N students in a class, where the i-th student has a score of AiAi.

The i-th student will boast if and only if the number of students scoring less than or equal Ai is greater than the number of students scoring greater than Ai.

Find the number of students who will boast.

### Input Format

• The first line contains T- the number of test cases. Then the test cases follow.
• The first line of each test case contains a single integer N – the number of students.
• The second line of each test case contains N integers A1,A2,…,AN – the scores of the students.

### Output Format

For each test case, output in a single line the number of students who will boast.

### Constraints

• 1≤T≤10001≤T≤1000
• 1≤N≤1001≤N≤100
• 0≤Ai≤100

### Sample Input 1

``````
3
3
100 100 100
3
2 1 3
4
30 1 30 30``````

```3
2
3
```

### Average Flex CodeChef Solutions in JAVA

```import java.util.Scanner;
public class Main {
static final int LIMIT = 100;
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int T = sc.nextInt();
for (int tc = 0; tc < T; ++tc) {
int N = sc.nextInt();
int[] A = new int[N];
for (int i = 0; i < A.length; ++i) {
A[i] = sc.nextInt();
}
System.out.println(solve(A));
}
sc.close();
}
static int solve(int[] A) {
int[] counts = new int[LIMIT + 1];
for (int score : A) {
++counts[score];
}
int result = 0;
int greaterNum = 0;
for (int i = counts.length - 1; i >= 0; --i) {
if (A.length - greaterNum > greaterNum) {
result += counts[i];
}
greaterNum += counts[i];
}
return result;
}
}```

### Average Flex CodeChef Solutions in CPP

```#include<iostream>
using namespace std;
int main()
{
int n;
cin>>n;
while (n--)
{
int a;
cin>>a;
int arr[a];
int sum=0;
for (int i = 0; i < a; i++)
{
cin>>arr[i];
}
for (int i = 0; i < a; i++)
{
int count=0;
for (int j = 0; j < a; j++)
{
if (arr[i]<arr[j])
count++;
}
if (count<a-count)
sum++;
}
cout<<sum<<endl;
}
return 0;
}```

### Average Flex CodeChef Solutions in Python

```t = int(input())
for i in range(t):
n = int(input())
l = list(map(int, input().split()))
c = 0
for j in l:
s = 0
k = 0
for z in l:
if z <= j:
s += 1
elif z > j:
k += 1
if s > k:
c += 1
print(c)```

Disclaimer: The above Problem (Average Flex) is generated by CodeChef but the solution is provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.

Note:- I compile all programs, if there is any case program is not working and showing an error please let me know in the comment section. If you are using adblocker, please disable adblocker because some functions of the site may not work correctly.