# Buggy Calculator Codechef Solution

#### ByBrokenprogrammers

Dec 19, 2022

Hello Programmers In this post, you will know how to solve the Buggy Calculator Codechef Solution.

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Codechef by yourself. If you find any difficulty after trying several times, then you can look for solutions.

### Problem

Trans bought a calculator at creatnx’s store. Unfortunately, it is fake. It has many bugs. One of them is adding two numbers without carrying. Example expression: 12 + 9 will have result 11 in his calculator. Given an expression in the form a + b, please output result from that calculator.

### Input

The first line contains an integer T denote the number of test cases. Each test case contains two integers a, b in a single line.

### Output

Each test case, print answer in a single line.

### Constraints

• 1 ≤ T ≤ 100
• 1 ≤ a, b ≤ 109

• Subtask #1 (30 points): 1 ≤ a, b ≤ 9
• Subtask #2 (70 points): original constrains

```2
12 9
25 25
```

```11
40```

### Buggy Calculator CodeChef Solutions in JAVA

```import java.util.*;
import java.lang.*;
import java.io.*;
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int tcases = sc.nextInt();
while(tcases-->0)
{
int a = sc.nextInt();
int b = sc.nextInt();
int sum=0;
int count=0;
while(a>0 || b>0)
{
int dig = ((a%10)+(b%10))%10;
sum = dig*(int)Math.pow(10,count)+sum;
a=a/10;
b=b/10;
count++;
}
System.out.println(sum);
}
}
}
```

### Buggy Calculator CodeChef Solutions in CPP

```#include <iostream>
using namespace std;
int main() {
int t;
cin>>t;
while(t--){
int a,b,r1,r2,res,f=1,sum=0;
cin>>a>>b;
while(a>0 || b>0)
{
r1=a%10;
r2=b%10;
res=(r1+r2)%10;
sum+=res*f;
f*=10;
a=a/10;
b=b/10;
}
cout<<sum<<endl;
}
return 0;
}```

### Buggy Calculator CodeChef Solutions in Python

```import math
def xsum(a,b):
multiplier=1
bit_sum=0
res=0
while(a or b):
bit_sum=((a%10) +(b%10))
bit_sum=bit_sum%10
res=(bit_sum*multiplier)+res
a=math.floor(a/10)
b=math.floor(b/10)
multiplier=multiplier*10
return res
for i in range(int(input())):
a,b=map(int,input().split())
print(xsum(a,b))```

Disclaimer: The above Problem (Buggy Calculator ) is generated by CodeChef but the solution is provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.

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