Default Arguments in Python HackerRank Solution

Hello Programmers, In this post, you will know how to solve the Default Arguments in Python HackerRank Solution. This problem is a part of the HackerRank Python Programming Series.

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One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.

Default Arguments in Python HackerRank Solution

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In this challenge, the task is to debug the existing code to successfully execute all provided test files.
Python supports a useful concept of default argument values. For each keyword argument of a function, we can assign a default value which is going to be used as the value of said argument if the function is called without it. For example, consider the following increment function: 

def increment_by(n, increment=1):
    return n + increment

 The functions works like this:

>>> increment_by(5, 2)
7
>>> increment_by(4)
5
>>>

 Debug the given function print_from_stream using the default value of one of its arguments.
The function has the following signature:

def print_from_stream(n, stream)

This function should print the first n values returned by get_next() method of stream object provided as an argument. Each of these values should be printed in a separate line. Whenever the function is called without the stream argument, it should use an instance of EvenStream class defined in the code stubs below as the value of stream.
Your function will be tested on several cases by the locked template code.

Input Format :

The input is read by the provided locked code template. In the first line, there is a single integer q denoting the number of queries. Each of the following line q contains a stream_name followed by integer n, and it corresponds to a single test for your function. 

Constraints :

• 1 <= q <= 100
• 1 <= N <= 10

Output Format :

The output is produced by the provided and locked code template. For each of the queries (stream_name, n), if the stream_name is even then print_from_stream(n) is called. Otherwise, if the stream_name is odd, then print_from_stream(n, OddStream()) is called.

Sample Input :

3
odd 2
even 3
odd 5

Sample Output :

1
3
0
2
4
1
3
5
7
9

Explanation :

There are 3 queries in the sample.
In the first query, the function print_from_stream(2, OddStream()) is exectuted, which leads to printing values 1 and 3 in separated lines as the first two non-negative odd numbers.In the second query, the function print_from_stream(3) is exectuted, which leads to printing values 2, 4 and 6 in separated lines as the first three non-negative even numbers.In the third query, the function print_from_stream(5, OddStream()) is exectuted, which leads to printing values 1, 3, 5, 7 and 9 in separated lines as the first five non-negative odd numbers. 

Default Arguments in Python HackerRank Solution

class EvenStream(object):
    def __init__(self):
        self.current = 0
    def get_next(self):
        to_return = self.current
        self.current += 2
        return to_return
class OddStream(object):
    def __init__(self):
        self.current = 1
    def get_next(self):
        to_return = self.current
        self.current += 2
        return to_return
# Default Arguments in Python - Hacker Rank Solution START ----->
def print_from_stream(n, stream=None):
    if stream is None:
        stream = EvenStream()
# Default Arguments in Python - Hacker Rank Solution END ----->
    for _ in range(n):
        print(stream.get_next())
queries = int(input())
for _ in range(queries):
    stream_name, n = input().split()
    n = int(n)
    if stream_name == "even":
        print_from_stream(n)
    else:
        print_from_stream(n, OddStream())

Disclaimer: The above Problem (Default Arguments in Python) is generated by Hackerrank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.

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