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DefaultDict Tutorial in Python HackerRank Solution
The defaultdict tool is a container in the collections class of Python. It’s similar to the usual dictionary (dict) container, but the only difference is that a defaultdict will have a default value if that key has not been set yet. If you didn’t use a defaultdict you’d have to check to see if that key exists, and if it doesn’t, set it to what you want.
For Example :
from collections import defaultdict d = defaultdict(list) d['python'].append("awesome") d['something-else'].append("not relevant") d['python'].append("language") for i in d.items(): print i
This prints :
('python', ['awesome', 'language']) ('something-else', ['not relevant'])
In this challenge, you will be given 2 integers, n and m. There are n words, which might repeat, in word group A. There are m words belonging to word group B. For each m words, check whether the word has appeared in group A or not. Print the indices of each occurrence of m in group A. If it does not appear, print -1.
- 1 <= n <= 10000
- 1 <= m <= 100
- 1 <= length of each word in the input <= 100
Input Format :
The first line contains integers, n and m separated by a space.
The next n lines contains the words belonging to group A.
The next m lines contains the words belonging to group B.
Output Format :
Output m lines.
The ith line should contain the 1-indexed positions of the occurrences of the ith word separated by spaces.
Sample Input :
5 2 a a b a b a b
Sample Output :
1 2 4 3 5
‘a’ appeared 3 times in positions 1, 2 and 4.
‘b’ appeared 2 times in positions 3 and 5.
In the sample problem, if ‘c’ also appeared in word group B, you would print -1.
DefaultDict Tutorial in Python HackerRank Solutions
# DefaultDict Tutorial in Python - Hacker Rank Solution # Python 3 # Enter your code here. Read input from STDIN. Print output to STDOUT # DefaultDict Tutorial in Python - Hacker Rank Solution START from collections import defaultdict n, m = map(int,input().split()) a = defaultdict(list) for i in range(1, n + 1): a[input()].append(i) for i in range(1, m + 1): key = input() if len(a[key]) > 0: print(" ".join(str(c) for c in a[key])) else: print(-1)
Disclaimer: The above Problem (DefaultDict Tutorial in Python) is generated by Hackerrank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.
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