# HackerRank Strange Counter Solution

#### ByBrokenprogrammers

Dec 12, 2022

Hello Programmers, In this post, you will know how to solve the HackerRank Strange Counter Solution. This problem is a part of the HackerRank Algorithms Series.

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.

## HackerRank Strange Counter Solution

There is a strange counter. At the first second, it displays the number 3. Each second, the number displayed by decrements by 1 until it reaches 1. In next second, the timer resets to 2 x the initial number for the prior cycle and continues counting down. The diagram below shows the counter values for each time t in the first three cycles:

Find and print the value displayed by the counter at time t.

Function Description

Complete the strangeCounter function in the editor below.

strangeCounter has the following parameter(s):

• int t: an integer

Returns

• int: the value displayed at time t.

Input Format

A single integer, the value of t.

Constraints

• 1 <= t <= 1012

• 1 <= t <= 105 for 60% of the maximum score

Sample Input

4

Sample Output

6

Explanation

Time t = 4 marks the beginning of the second cycle. It is double the number displayed at the beginning of the first cycle: 2 x 3 = 6. This is shown in the diagram in the problem statement.

## HackerRank Strange Counter Solution

### Strange Counter Solution in C

```#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main() {
long long n,f=3;
scanf("%lld",&n);
while(n>f) n-=f,f*=2;
printf("%lld\n",f-n+1);
return 0;
}```

### Strange Counter Solution in Cpp

```#include <fstream>
#include <iostream>
#include <string>
#include <complex>
#include <math.h>
#include <set>
#include <vector>
#include <map>
#include <queue>
#include <stdio.h>
#include <stack>
#include <algorithm>
#include <list>
#include <ctime>
#include <memory.h>
#include <assert.h>
#define y0 sdkfaslhagaklsldk
#define y1 aasdfasdfasdf
#define j1 assdgsdgasghsf
#define tm sdfjahlfasfh
#define lr asgasgash
#define norm asdfasdgasdgsd
#define eps 1e-9
#define M_PI 3.141592653589793
#define bs 1234567891
#define bsize 350
using namespace std;
const int INF = 1e9;
const int N = 200000;
long long n;
int main(){
//freopen("fabro.in","r",stdin);
//freopen("fabro.out","w",stdout);
//freopen("F:/in.txt", "r", stdin);
//freopen("F:/output.txt", "w", stdout);
ios_base::sync_with_stdio(0);
//cin.tie(0);
cin >> n;
long long P = 3;
while (n > P)
{
n -= P;
P *= 2;
}
cout << P - n + 1 << endl;
cin.get(); cin.get();
return 0;
}```

### Strange Counter Solution in Java

```import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
long t = sc.nextLong();
long curr = 3;
while (t > curr) {
t -= curr;
curr *= 2;
}
System.out.println(curr-t+1);
}
}```

### Strange Counter Solution in Python

```t = input()
start = 0
interval = 3
while t > start + interval:
start += interval
interval *= 2
offset = t - start
print interval - offset + 1```

### Strange Counter Solution using JavaScript

```function processData(input) {
let n = parseInt(input);
let l2 = Math.ceil(Math.log2(n / 3 + 1));
let s = 3 * (Math.pow(2, l2 - 1));
let s2 = s - 2;
let index = n - s2;
//console.log(l2, s, index, s - index);
console.log(s - index);
}
process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
_input += input;
});
process.stdin.on("end", function () {
processData(_input);
});```

### Strange Counter Solution in Scala

```object Solution {
def main(args: Array[String]) {
/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution
*/
io.Source.stdin.getLines.map{ _.toLong }.foreach { t =>
@scala.annotation.tailrec
def helper( x: Long, v: Long ): Long = {
if ( x <= v ) {
(v - x) + 1
} else {
helper( x - v, v * 2 )
}
}
println( helper( t, 3 ) )
}
}
}```

### Strange Counter Solution in Pascal

```const
inp = 'input.txt';
out = 'output.txt';
var
n, time, val : int64;
procedure       init;
begin
end;
procedure       solve;
var L : int64;
begin
time := 1; val := 3;
while (time + val <= n) do
begin
time := time + val;
val := val * 2;
end;
L := n - time;
val := val - L;
writeln(val);
end;
begin
//assign(input, inp); reset(Input);
//assign(output, out); rewrite(output);
init;
solve;
end.```

Disclaimer: This problem (Strange Counter) is generated by HackerRank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.