Java If-Else HackerRank Solution

Hello Programmers, In this post, you will know how to solve the Java If-Else HackerRank Solution. This problem is a part of the HackerRank Java Programming Series.

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.

Java If-Else HackerRank Solution

Problem

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Task

Given an integer, n, perform the following conditional actions:

• If n is odd, print Weird
• If n is even and in the inclusive range of 2 to 5, print Not Weird
• If n is even and in the inclusive range of 6 to 20 , print Weird
• If n is even and greater than 20, print Not Weird

Complete the stub code provided in your editor to print whether or not n is weird.

Input Format

A single line containing a positive integer, n.

Constraints

1<=n<=100

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Example 0 :-

Sample Input 0

3

Sample Output 0

Weird

Example 1 :-

Sample Input 1

24

Sample Output1

Not Weird

Explanation

Sample Case 0: n=3n is odd and odd numbers are weird, so we print Weird.Sample Case 1:n=24 n>24 and n is even, so it isn’t weird. Thus, we print Not Weird.

Java If-Else HackerRank Solutions

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
public class Solution
{
    private static final Scanner scanner = new Scanner(System.in);
    public static void main(String[] args)
 {
        int N = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
        if(N%2!=0)
        {
            System.out.println("Weird");
        }
        else if(N >=2&&N<=5)
        {
            System.out.println("Not Weird");
        }
        else if(N>=6 && N <= 20)
        {
            System.out.println("Weird");
        }
        else if(N>=20)
        {
            System.out.println("Not Weird");
        }
        scanner.close();
    }
}

Disclaimer: The above Problem (Java If-Else) is generated by Hackerrank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.

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