Java Interface HackerRank Solution

Hello Programmers, In this post, you will know how to solve the Java Interface HackerRank Solution. This problem is a part of the HackerRank Java Programming Series.

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.

Java Interface HackerRank Solution

Problem

A Java interface can only contain method signatures and fields. The interface can be used to achieve polymorphism. In this problem, you will practice your knowledge on interfaces.

You are given an interface AdvancedArithmetic which contains a method signature int divisor_sum(int n). You need to write a class called MyCalculator which implements the interface.

divisorSum function just takes an integer as input and return the sum of all its divisors. For example divisors of 6 are 1, 2, 3 and 6, so divisor_sum should return 12. The value of n will be at most 1000.

Read the partially completed code in the editor and complete it. You just need to write the MyCalculator class only. Your class shouldn’t be public.

Sample Input

6

Sample Output

I implemented: AdvancedArithmetic
12

Explanation

Divisors of 6 are 1,2,3 and 6. 1+2+3+6=12

Java Interface HackerRank Solutions

import java.util.*;
interface AdvancedArithmetic{
  int divisor_sum(int n);
}
//Write your code here
class MyCalculator implements AdvancedArithmetic {
    public int divisor_sum(int n) {
        int sum=0;
        for(int i=1;i<=n;i++) {
            if(n%i==0)
                sum+=i;
        }
        return sum;
    }
}
class Solution{
    public static void main(String []args){
        MyCalculator my_calculator = new MyCalculator();
        System.out.print("I implemented: ");
        ImplementedInterfaceNames(my_calculator);
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        System.out.print(my_calculator.divisor_sum(n) + "\n");
      	sc.close();
    }
    /*
     *  ImplementedInterfaceNames method takes an object and prints the name of the interfaces it implemented
     */
    static void ImplementedInterfaceNames(Object o){
        Class[] theInterfaces = o.getClass().getInterfaces();
        for (int i = 0; i < theInterfaces.length; i++){
            String interfaceName = theInterfaces[i].getName();
            System.out.println(interfaceName);
        }
    }
}

Disclaimer: The above Problem (Java Interface) is generated by Hackerrank but the Solution is Provided by  BrokenProgrammers. This tutorial is only for Educational and Learning purposes.

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