# Java Map HackerRank Solution

#### ByBrokenprogrammers

Dec 4, 2022

Hello Programmers, In this post, you will know how to solve the Java Map HackerRank Solution. This problem is a part of the HackerRank Java Programming Series.

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.

## Java Map HackerRank Solution

### Problem

You are given a phone book that consists of people’s names and their phone number. After that you will be given some person’s name as query. For each query, print the phone number of that person.

Input Format

The first line will have an integer  denoting the number of entries in the phone book. Each entry consists of two lines: a name and the corresponding phone number.

After these, there will be some queries. Each query will contain a person’s name. Read the queries until end-of-file.

Constraints:
A person’s name consists of only lower-case English letters and it may be in the format ‘first-name last-name’ or in the format ‘first-name’. Each phone number has exactly 8 digits without any leading zeros.

Output Format

For each case, print “Not found” if the person has no entry in the phone book. Otherwise, print the person’s name and phone number. See sample output for the exact format.

To make the problem easier, we provided a portion of the code in the editor. You can either complete that code or write completely on your own.

Sample Input

``````3
uncle sam
99912222
tom
11122222
harry
12299933
uncle sam
uncle tom
harry
``````

Sample Output

``````uncle sam=99912222
harry=12299933``````

### Java Map HackerRank Solution

```import java.util.*;
import java.io.*;
class Solution{
public static void main(String []argh)
{
HashMap<String, Integer> hash = new HashMap<String, Integer>();
Scanner in = new Scanner(System.in);
int n=in.nextInt();
in.nextLine();
for(int i=0;i<n;i++)
{
String name=in.nextLine();
int phone=in.nextInt();
hash.put(name, phone);
in.nextLine();
}
while(in.hasNext())
{
String s=in.nextLine();
if (hash.containsKey(s)) {
System.out.println(s + "=" + hash.get(s));
} else {
}
}
}
}```

Disclaimer: The above Problem (Java Map) is generated by Hackerrank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.