Hello Programmers, In this post, you will know how to solve the Java Regex HackerRank Solution. This problem is a part of the HackerRank Java Programming Series.
One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.
Java Regex HackerRank Solution
Problem :
Write a class called MyRegex which will contain a string pattern. You need to write a regular expression and assign it to the pattern such that it can be used to validate an IP address. Use the following definition of an IP address:
IP address is a string in the form "A.B.C.D", where the value of A, B, C, and D may range from 0 to 255. Leading zeros are allowed. The length of A, B, C, or D can't be greater than 3.
Some valid IP address:
000.12.12.034 121.234.12.12 23.45.12.56
Some invalid IP address:
000.12.234.23.23 666.666.23.23 .213.123.23.32 23.45.22.32. I.Am.not.an.ip
In this problem you will be provided strings containing any combination of ASCII characters. You have to write a regular expression to find the valid IPs.
Just write the MyRegex class which contains a String . The string should contain the correct regular expression.
(MyRegex class MUST NOT be public)
Sample Input
000.12.12.034
121.234.12.12
23.45.12.56
00.12.123.123123.123
122.23
Hello.IP
Sample Output
true
true
true
false
false
false
Java Regex HackerRank Solutions
import java.util.regex.Matcher; import java.util.regex.Pattern; import java.util.Scanner; class Solution{ public static void main(String[] args){ Scanner in = new Scanner(System.in); while(in.hasNext()){ String IP = in.next(); System.out.println(IP.matches(new MyRegex().pattern)); } } } /* [01]?\\d{1,2} matches numbers 0-199. 2[0-4]\\d matches numbers 200-249 25[0-5] matches numbers 250-255 */ class MyRegex { String num = "([01]?\\d{1,2}|2[0-4]\\d|25[0-5])"; String pattern = num + "." + num + "." + num + "." + num; }
Disclaimer: The above Problem (Java Regex) is generated by Hackerrank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.