# Search Insert Position Leetcode Solution

Dec 1, 2022

In this post, you will know how to solve the Search Insert Position Leetcode Solution problem of Leetcode. This Leetcode problem is done in many programming languages like C++, Java, and Python.

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Leetcode by yourself. If you find any difficulty after trying several times, then you can look for solutions.

## Problem

Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You must write an algorithm with `O(log n)` runtime complexity.

Example 1:

```Input: nums = [1,3,5,6], target = 5
Output: 2
```

Example 2:

```Input: nums = [1,3,5,6], target = 2
Output: 1
```

Example 3:

```Input: nums = [1,3,5,6], target = 7
Output: 4
```

Constraints:

• `1 <= nums.length <= 104`
• `-104 <= nums[i] <= 104`
• `nums` contains distinct values sorted in ascending order.
• `-104 <= target <= 104`

### Search Insert Position Leetcode Solutions in Python

```class Solution:
def searchInsert(self, nums: List[int], target: int) -> int:
l = 0
r = len(nums)
while l < r:
m = (l + r) // 2
if nums[m] == target:
return m
if nums[m] < target:
l = m + 1
else:
r = m
return l
```

### Search Insert PositionLeetcode Solutionsin CPP

```class Solution {
public:
int searchInsert(vector<int>& nums, int target) {
int l = 0;
int r = nums.size();
while (l < r) {
const int m = (l + r) / 2;
if (nums[m] == target)
return m;
if (nums[m] < target)
l = m + 1;
else
r = m;
}
return l;
}
};
```

### Search Insert Position Leetcode Solutions in Java

```class Solution {
public int searchInsert(int[] nums, int target) {
int l = 0;
int r = nums.length;
while (l < r) {
final int m = (l + r) / 2;
if (nums[m] == target)
return m;
if (nums[m] < target)
l = m + 1;
else
r = m;
}
return l;
}
}
```

Note: This problem Search Insert Position is generated by Leetcode but the solution is provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.