# Zipped in python HackerRank Solution

#### ByBrokenprogrammers

Dec 9, 2022

Hello Programmers, In this post, you will know how to solve the Zipped in python HackerRank Solution. This problem is a part of the HackerRank Python Programming Series.

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.

## Zipped in python HackerRank Solution

### Problem

zip([iterable, …])
This function returns a list of tuples. The i th tuple contains the i th element from each of the argument sequences or iterables.
If the argument sequences are of unequal lengths, then the returned list is truncated to the length of the shortest argument sequence.
Sample Code :

```>>> print zip([1,2,3,4,5,6],'Hacker')
[(1, 'H'), (2, 'a'), (3, 'c'), (4, 'k'), (5, 'e'), (6, 'r')]
>>>
>>> print zip([1,2,3,4,5,6],[0,9,8,7,6,5,4,3,2,1])
[(1, 0), (2, 9), (3, 8), (4, 7), (5, 6), (6, 5)]
>>>
>>> A = [1,2,3]
>>> B = [6,5,4]
>>> C = [7,8,9]
>>> X = [A] + [B] + [C]
>>>
>>> print zip(*X)
[(1, 6, 7), (2, 5, 8), (3, 4, 9)]
```

#### Task :

The National University conducts an examination of  N students in X subjects.
Your task is to compute the average scores of each student.

The format for the general mark sheet is:

```Student ID → ___1_____2_____3_____4_____5__
Subject 1   |  89    90    78    93    80
Subject 2   |  90    91    85    88    86
Subject 3   |  91    92    83    89    90.5
|______________________________
Average        90    91    82    90    85.5
```

#### Input Format :

The first line contains N and X separated by a space.
The next X lines contains the space separated marks obtained by students in a particular subject.

• 0 < N <= 100
• 0 < X <= 100

#### Output Format :

Print the averages of all students on separate lines.
The averages must be correct up to 1 decimal place.

```5 3
89 90 78 93 80
90 91 85 88 86
91 92 83 89 90.5
```

```90.0
91.0
82.0
90.0
85.5
```

#### Explanation :

Marks obtained by student 1: 89 90 91
Average marks of student 1:
270 / 3 = 90.0
Marks obtained by student 2: 90 91 92
Average marks of student 2:
273 / 3 = 91.0
Marks obtained by student 3: 78 85 83
Average marks of student 3:
246 / 3 = 82.0
Marks obtained by student 4: 93 88 89
Average marks of student 4:
270 / 3 = 90.0
Marks obtained by student 5: 80 86 90.5
Average marks of student 5:256.5 / 3 = 85.5

### Zipped in python HackerRank Solution

```N, X = input().split()
io = list()
for _ in range(int(X)):
ip = map(float, input().split())
io.append(ip)
for i in zip(*io):
print( sum(i)/len(i) ) ```

Disclaimer: The above Problem (Zipped in python) is generated by Hackerrank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.