# For Loop in C HackerRank Solution

Hello Programmers, In this post, you will know how to solve the For Loop in C HackerRank Solution. This problem is a part of the HackerRank C Programming Series.

One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.

## For Loop in C

### Objective

In this challenge, you will learn the usage of the for loop, which is a programming language statement which allows code to be repeatedly executed.
The syntax for this is

```for ( <expression_1> ; <expression_2> ; <expression_3> )
<statement>```
• expression_1 is used for initializing variables which are generally used for controlling the terminating flag for the loop.
• expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
• expression_3 is generally used to update the flags/variables

A sample loop will be

```for(int i = 0; i < 10; i++) {
...
}```

For each integer n in the interval [a,b] (given as input) :

•  If 1<= n , then print the English representation of it in lowercase. That is “one” for 1, “two” for 2, and so on.
• Else if n > 9 and it is an even number, then print “even”.
• Else if n < 9 and it is an odd number, then print “odd”.

#### Input Format

The first line contains an integer, a.The second line contains an integer, b.

1<=a<=b<=10^6

#### Output Format

Print the appropriate English representation,`even`, or `odd`, based on the conditions described in the ‘task’ section.

```8
11```

```eight
nine
even
odd```

### For Loop in C HackerRank Solution

```#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main()
{
int a, b;
scanf("%d\n%d", &a, &b);
// Complete the code.
// For Loop in C - Hacker Rank Solution START
char *str[] = {"one", "two", "three", "four", "five", "six", "seven",  "eight",  "nine", "even", "odd"};
scanf("%d\n%d", &a, &b);
for (int i=a; i<=b; i++)// i= 8
{
if (i <= 9)
{
printf ("%s\n", str[i-1]);
}
else
{
printf ("%s\n", str[9+(i%2)]);
}
// For Loop in C - Hacker Rank Solution END
}
return 0;
}```

Disclaimer: The above Problem (For Loop in C) is generated by Hackerrank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.

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