Hello Programmers, In this post, you will know how to solve the For Loop in C++ HackerRank Solution. This problem is a part of the HackerRank C++ Programming Series.
One more thing to add, don’t directly look for the solutions, first try to solve the problems of Hackerrank by yourself. If you find any difficulty after trying several times, then you can look for solutions.
For Loop in C++ HackerRank Solution
Objectives
A for loop is a programming language statement which allows code to be repeatedly executed.
The syntax for this isSyntax :
for ( <expression_1> ; <expression_2> ; <expression_3> )
<statement>
- expression_1 is used for intializing variables which are generally used for controlling terminating flag for the loop.
- expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
- expression_3 is generally used to update the flags/variables.
- A sample loop will be
Example :
for(int i = 0; i < 10; i++) {
...
}
Input Format
You will be given two positive integers, a and b (a<=b), separated by a newline.
Output Format
For each integer n, in the interval [a,b]:
- If 1<=n<=9 then print the English representation of it in lowercase. That is “one” for 1, “two” for 2, and so on.
- Else if n>9 and it is an even number, then print “even”.
- Else if n>9 and it is an odd number, then print “odd”.
Sample Input
8 11
Sample Output
eight nine even odd
For Loop in C++ HackerRank Solutions
#include <iostream>
#include <cstdio>
using namespace std;
int main() {
// Complete the code.
int a,b,i;
char *str[] = {"one","two","three","four","five","six","seven","eight","nine","even","odd"};
cin>>a;
cin>>b;
for(i=a;i<=b;i++)
{
if(i<=9)
{
cout<<str[i-1]<<"\n";
}
else
{
cout<<str[9+(i%2)]<<"\n";
}
}
return 0;
}Disclaimer: The above Problem (For Loop in C++) is generated by Hackerrank but the Solution is Provided by BrokenProgrammers. This tutorial is only for Educational and Learning purposes.
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